A conical tube of length 2m is fixed vertically with its smaller end upwards. The velocity of flow at smaller,

Question

end is 2.5m of liquid. The loss of head in tube is 0.35*(v1-v2)^2/2g, where v1 is the velocity at the smaller end & v2 at the lower end. Determine the pressure head at the lower end. Flow take place in the down ward direction...( question of fluid flow operation..related to chemical engg..)

Answer 1

The information supplied is insufficient for a numeric answer, because to know v2 one would have to know the area ratio of the two ends. However suppose we refer to the smaller/larger ratio as N. Then v2=2.5*N, and the equation for head loss dH becomes 0.35*(2.5*(1-N))^2/(2*g). The total head is 2 - dH m.