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The index of refraction for silicate flint glass is 1.66 for light with a wavelength of 400 nm and 1.61 for light with a wavelength of 700 nm.

Find the angles of refraction for light of these wavelengths that is incident on this glass at an angle of 45 degree.

2007-04-30 16:49:20 · 2 answers · asked by hpage 3 in Science & Mathematics Engineering

2 answers

θ = sin^-1((1/1.66)sin(45°) = 25.2°
θ = sin^-1((1/1.61)sin(45°) = 26°

2007-04-30 17:54:14 · answer #1 · answered by Helmut 7 · 0 0

A: 46.8 deg

2007-04-30 23:57:44 · answer #2 · answered by Holden® [ThumbZUP] tRoLL PaTrOL 6 · 0 1

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