A transformer has 400 turns in the primary and 8 turns in the secondary.
(a) Is this a step-up or a step-down transformer?
(b) If the primary is connected across 120 V rms, what is the open-circuit voltage across the secondary?
(c) If the primary current is 0.1A, what is the secondary current, assuming negligible magnetization current and no power loss?
2007-04-30 16:28:20 · 5 answers · asked by hpage 3 in Science & Mathematics ➔ Engineering
(a) Step-down, less turns in secondary means step-down.
(b) 2.4V, (nP/nS) x Vin=Vout, (8/400) x 120=Vout
(c) 5A, (nS/nP) x Iin=Iout, (400/8) x 0.1=Iout.
Hope this was helpful.
2007-04-30 16:42:29 · answer #1 · answered by charley128 5 · 0⤊ 0⤋
I'm not an electrical engineer, but I think the answers are as follows:
(a) step-down
(b) 120 (8/400) = 2.4 V rms
(c) 0.1A (120 V) = ? A (2.4 V)
Current = 5 A
2007-04-30 23:38:42 · answer #2 · answered by actuator 5 · 0⤊ 0⤋
400:8 is definitely a step down. Understand that you're trading current for voltage.
Multiply 120 by (8/400) = 2.4V
It all works in reverse for the current
Multiply 0.1 by (400/8) = 5 amps
2007-04-30 23:35:14 · answer #3 · answered by C Anderson 5 · 0⤊ 0⤋
1. If you're considering the primary as the input, it's a step-down transformer. If the secondary is the input, then it's a step-up transformer.
2. 2.4 VAC
3. 26.6 amps
2007-04-30 23:38:48 · answer #4 · answered by ? 6 · 0⤊ 1⤋
wow. i have no idea what you're talking about.
2007-04-30 23:30:55 · answer #5 · answered by BRobb 3 · 0⤊ 1⤋