P = I * V so you need to know the voltage as well as the amps and rms or peak?
2007-04-28 15:24:46
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answer #1
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answered by Daniel H 5
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It depends on the load. The amount of power delivered to a circuit is measured by the Voltage multiplied by the Current. Since Voltage is equal to Current multiplied by Resistance, the power is equal to the Current squared multiplied by the Resistance, or P = I^2 * R
So, if you have a one ohm load (very unlikely), your power is equal to 11^2 * 1 or 121 Watts.
2007-04-28 15:28:15
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answer #2
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answered by Bigfoot 7
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celebration a million. a gadget it really is categorized 10 amps @ 10 volts, signifies that in case you observe 10 volts to that gadget 10 amps will bypass. If ten amps flows you'll expend one hundred watts of capacity. celebration 2. a gadget categorized one hundred amps @ a million volt skill precisely that, in case you observe a million volt to this gadget one hundred amps will bypass. back the capacity dissipated will be one hundred watts. It skill precisely what it says. The lacking element on your celebration is the resistance. Resistance = the voltage divided through the amps. So in celebration a million, the resistance might want to be a million ohm. In celebration 2 the resistance might want to be .001 ohms.
2016-12-05 01:09:40
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answer #3
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answered by Anonymous
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amps and watts are two different types of units
amp is charge over time which is coulombs/sec
watts is work/energy over time which is joules/sec
amperage measure current while watts measure power
2007-04-28 16:31:22
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answer #4
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answered by black_lotus007@sbcglobal.net 3
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P = VI
P = I^2R
You must know either the voltage or resistance to get power from current.
2007-04-28 16:31:33
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answer #5
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answered by Helmut 7
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If the voltage is 110 (US).
110 x 11 = 1.210kW
2007-04-28 18:00:12
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answer #6
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answered by Norrie 7
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are you serious?
Watts is a unit of power, Amps is current.
Watts = Amps*Volts.
2007-04-28 17:07:28
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answer #7
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answered by Anonymous
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