how could i calculate the pressure of a liquid pump, in P.S.I. ? i know the pumps displacement, rpm, and input power, and will be using water as my baseline liquid.
2007-04-28 04:20:35 · 4 answers · asked by commanderkraut 1 in Science & Mathematics ➔ Engineering
These equations aren't exact, but should get you pretty near the right answer. I've included some examples to show you how to apply them. If your units are different just convert them, that shouldn't be a problem.
Pump Output Flow (in Gallons Per Minute)
RPM X Pump Displacement / 231
How much oil will be produced by a 2.21 cubic inch pump operating at 1120 rpm?
RPM = 1120
Pump Displacement = 2.21 cubic inches
RPM X Pump Displacement / 231 = 1120 X 2.21 / 231 = 10.72 gpm
Horsepower Required to Drive Pump (used to find outlet pressure)
HP X Efficiency = GPM X PSI X .0007 (this is a 'rule-of-thumb' calculation, based on the viscosity of the liquid) Just solve for PSI instead of HP if you know your input power. We'll assume 100% efficiency for the example, but that's never the case.
How many horsepower are needed to drive a 10 gpm pump at 1750 psi?
GPM = 10
PSI = 1750
GPM X PSI X .0007 / 100% = 10 X 1750 X .0007 / 100% = 12.25 horsepower (theoretical)
2007-04-28 07:10:57 · answer #1 · answered by Bigsky_52 6 · 0⤊ 0⤋
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2016-12-05 00:33:45 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Brake HP = gpm x psi/1714 x pump efficiency
or
psi = (Brake HP) x pump efficiency x 1714/gpm
Pump efficiency = Hydraulic HP/Brake HP
2007-04-28 06:58:39 · answer #3 · answered by gatorbait 7 · 0⤊ 0⤋
The formula is in a book called The Flow of Fluids.
2007-04-28 04:29:10 · answer #4 · answered by Anonymous · 0⤊ 0⤋