2007-04-28 04:15:45 · 10 answers · asked by ROBERTA H 1 in Sports ➔ Boxing
Oscar by far, I read it somewhere that hes the sharpest managing his money and especially now that he is a promoter and gotten other fighters like Mosley and Hopkins to work with him in Golden Boy Productions... I could be wrong but what he makes with fights, promotions and endorsements his worth is over 500 million right now...definitely heads and shoulders above all the boxers who ever laced em up...and going up in value every day...
2007-04-28 09:46:45 · answer #1 · answered by doingitright44 6 · 0⤊ 0⤋
Don King, George Foreman, Bob Arum, Mike Tyson, Oscar De La Hoya
2007-04-28 16:30:16 · answer #2 · answered by JAM 4 · 0⤊ 0⤋
Oscar de la Hoya (USA) is the world's highest-paid boxer, with estimated earnings of $43.5 million in 1999, according to the Forbes Celebrity 100 List.
2007-04-28 04:18:49 · answer #3 · answered by c_crum 4 · 0⤊ 0⤋
If we are just talking about actual purses from fights i would say that Tyson may well be the biggest earner, i would say then that Lennox Lewis may well be the 2nd biggest earner. I think De La Hoya would be the biggest earning non-heavyweight.
2007-04-28 22:36:13 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Evander Holyfield
2007-04-28 04:19:45 · answer #5 · answered by reds141414 2 · 0⤊ 0⤋
Roy Jones Jr
2007-04-28 10:09:25 · answer #6 · answered by Cayden 2 · 0⤊ 0⤋
Don King
2007-04-28 04:23:34 · answer #7 · answered by Damon S 4 · 1⤊ 0⤋
Probably Don King. As for boxers, I would probably guess Lennox Lewis or Oscar Delahoya.
2007-04-28 04:40:13 · answer #8 · answered by Stephen L 6 · 0⤊ 0⤋
oscar de la hoya easily,don king is not a fighter and evander holyfield is a distant 3rd.de la hoya will get about 25-30 million for beating up fraud mayweather.mayweather will only get ten.
2007-04-28 04:46:15 · answer #9 · answered by ant c 1 · 0⤊ 0⤋
De La Hoya I hear is making 30 mil for the Mayweather fight, and that's not including PPV revenue, so I say him.
2007-04-28 13:47:24 · answer #10 · answered by mowglieboy 3 · 0⤊ 0⤋