2007-04-26 17:03:59 · 5 answers · asked by Lauren C 1 in Science & Mathematics ➔ Engineering
Let the width of the Rectangle be = x in
Then, the length of the rectangle is= 4x +2 inches
Area of the rectangle = l *w = x ( 4x +2)
= 4x^2 + 2x = 85 inches square
=> 4x^2 + 2x - 85 = 0
Slolve this quadractic equation to get the positive value of x
2007-04-26 17:18:17 · answer #1 · answered by Anonymous · 0⤊ 0⤋
If W is the width, then:
W*(W*4+2)=85
4W^2+2W-85=0
W=-2/8+SQRT(1/16+85/4)=4.3665463281548469694005443127081 (approximately),
and the length is 19.466185312619387877602177250832 (more or less) in inches.
Now, what was the question?
The color of the rectangle?
I would gess light green.
2007-04-26 17:16:27 · answer #2 · answered by singlepun 3 · 0⤊ 0⤋
l x w = 85
l = 2 + 4w
w = w
therefore:
(2+4w) x (w) =85
2w + 4w^2 = 85
use quadratic equation:
4w^2 + 2w - 85 = 0
solve for w and use positive value as w
2007-04-26 17:10:38 · answer #3 · answered by (+_+) B 4 · 0⤊ 0⤋
It can never be 85 in square
2007-04-27 00:13:51 · answer #4 · answered by annan 2 · 0⤊ 0⤋
L = 2 + 4W
LW = 85
4W^2 + 2W = 85
W = (-2 ± â(4 + 1360))/8
W = (-2 + â1364)/8
W = 4.3665 in
L = 19.466 in
2007-04-26 17:16:59 · answer #5 · answered by Helmut 7 · 0⤊ 0⤋