how many kva = 1 kwh?

Question

how many kva = 1 kwh

Answer 1

sorry can't co-relate.

1 kWh = 1.3428 hp-hr.

Answer 2

In DC kva is the same as kw. Multiply this by time and you get kwh.

For ac inductive loads apply the correction given in the other answers.

Unless a time is specified kva cannot be converted to kwh.

Answer 3

KVA x Cos phi (The power factor)= KW.

That is, KVA is virtual power, and KW is the real power, measured in kilowatts (1000 Watts= 1 KW).
The KW, when multiplied by the no.of hours over which it is measured, gives = KWH, the kilowatt-hour.
This KWH [ 1000 watts x hours] is also called 1 Unit of energy, for which the Utility company charges you a bill.

Answer 4

KVA is an unit for DC Power, where as KWH is the Unit for Energy.

So these two can't be co related

Answer 5

You're question is not right. Kva and kwh are not the same unit. If two unit are not the same they cannot be equalize.

Answer 6

Multiply kVA by power factor of load to get kWH.

Answer 7

KVA - Kilo volt amphere KWH - Kilo watts per hour difference between kva and Kwh areKilowatt (kW), kilowatt-hour (kWh), and kilovolt-ampere (kVA) are units of measure related to electricity. A brief explanation of each follows. Kilowatt-hour (kWh) is the measure of energy consumption (power over time). As an example, a 60-watt light bulb burns power at the rate of 60 watts (or 0.060 kW). In one hour, the bulb will consume 60 watts times 1 hour, or 60 watt-hours. In 12 hours, that same bulb will have consumed 60 watts times 12 hours, or 720 watt-hours (0.72 kWh). kWh is a unit of energy. Kilovolt-Ampere (kVA) is a unit of electrical power, often referred to as apparent power. This is what the utility must supply to its customers on the primary side of the facility transformer and is the basis for sizing power plants. Kilowatt (kW) is also a unit of electrical power (equal to 1,000 watts), referred to as real power. This measure of power is also called demand. This does real work. For a 60-watt bulb, the demand would be 60 watts. Different facilities may use the same amount of real power (kW), but different supply levels of apparent power (kVA) depending on the kind of equipment in the facilities. Equipment with numerous magnetic fields (like motors) will require more apparent power to feed the same real power demand. If you know the kilowatt demand (real power), then you can calculate the electrical energy consumed over time (kW x time = energy). There is also a relationship between real power and apparent power that is based on the concept of power factor. If you know your real power (kW) and your power factor, you can calculate your level of apparent power (kVA). Determining kVA and kWh power factor = kW/kVA or kVA = kW/power factor If the useful power that the customer consumes is described as real power (kW), the component of lost power is sometimes referred to as reactive power, or kilovolt amps reactive (kVAR). The total amount of power that the utility has to supply to the customer is given in kVA (referred to as apparent power). If all electric loads were resistive (as in incandescent lights, resistance heaters, and so forth), you would not have to worry about power factor. The electrical system would be operating at its highest efficiency. But there are also motors, transformers, and capacitors that are components of electrical systems, and these devices and others create induction and capacitance. The net effect of these inductive and capacitive devices results in inefficiency. When this happens, some of the energy is lost to generate the magnetic field of the motor, or the energy is lost in the creation of the stored energy for the capacitor.

Answer 8

1 KW = 1 KVA X COS(PHI)

POWER FACTOR = COS(PHI)

Answer 9

try google