Just another Maths Question, Umm
Well I dont know
I attempeted this one
I wrote 10(8x^2-2y^2)
is that right?
wrong?
can i do more?
2007-04-22 22:37:23 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
10(8x^2 - 2y^2) is a good start, but keep going.
Remember the difference of squares formula:
a^2 - b^2 = (a - b)(a + b)
10(8x^2 - 2y^2)
= 20(4x^2 - y^2)
= 20(2x - y)(2x + y)
2007-04-22 22:40:57 · answer #1 · answered by Mathematica 7 · 1⤊ 2⤋
80x^2 - 20y^2
= 20(4x^2 - y^2)
= 20(2x - y)(2x + y).
2007-04-23 05:41:16 · answer #2 · answered by Anonymous · 1⤊ 1⤋
Common factor first
80x² - 20y² =
20(4x² - y²) =
20(2x - y)(2x + y)
- - - - - - -s-
2007-04-23 08:23:48 · answer #3 · answered by SAMUEL D 7 · 1⤊ 1⤋
remove 20
20(4x^2 - y^2)
the brackets can be further factorised to give
20[(2x - y)(2x+y)]
2007-04-23 05:41:50 · answer #4 · answered by Riti 3 · 2⤊ 0⤋
20(4x^2-y^2)
20(2x+y)(2x-y)
2007-04-23 15:36:21 · answer #5 · answered by Anonymous · 1⤊ 0⤋
20(4x^2-y^2)
=20[(2x)^2-y^2]
=20(2x-y)(2x+y)
2007-04-23 05:58:10 · answer #6 · answered by ? 4 · 2⤊ 0⤋