Factorise: 2+ 1x - 3x^2 (so thats 3x squared)?

Question

I need help with this maths question.. Its due tomorrow
Along with a heap of others I cant do
It just says to Factorise, I hope you can help

Answer 1

2 + 1x - 3x² =

2 + 2x - 3x - 3x²

2(1 + x) - 3x(1 + x) = 0

(2 - 3x)(x + 1)

- - - - - - - - - -s-

Answer 2

As it somewhat is a non-monic expression (as a results of fact of this 3x^2 has a coefficient greater desirable than a million) initiate the factoring like this: [(3x )(3x )] / 3 Now multiply the coefficient of 3x^2 (3) against the product term (-2): 3 * -2 = -6 factors of -6 = +-(a million, 2, 3, 6) From the record of things locate 2 numbers that when extra at the same time supply -5 and while prolonged at the same time supply -6. a million and -6 extra at the same time supply -5 and prolonged at the same time supply -6 so plug those in: [(3x + a million)(3x - 6)] / 3 Now take out the utmost complication-loose ingredient between the two gadgets of brackets: [(3x + a million) 3(x - 2)] / 3 Simplify the fraction: (3x + a million)(x - 2)

Answer 3

Use the quadratic formula to find the roots of the polynomial, which in this case are x = 1 and x = -2/3. Then the answer will be A(x-1)(x+2/3) for some A. In this case you need the leading coefficent to be -3, so A = -3. The final answer is -3(x-1)(x+2/3) = -(x-1)(3x + 2).

Answer 4

First, you need to rearrange the equation to:
-3x^2 + x + 2

Then you do the cross multiplication method:
-3x -2
x -1

And this will work out to be:
(-3x-2)(x-1)

To check this, expand the brackets:
-3x^2 + 3x - 2x + 2 OR -3x^2 + 2 + x

I hope you found this useful = ]

NOTE:
(2 + 3x)(1 - x) is also correct.

If you expand the brackets, it'll also work out.

Answer 5

(2+3x)(1-x)

Answer 6

(2 + 3x)(1 - x).

Answer 7

-(3x^2 - x - 2) = -(3x^2 - 3x + 2x - 2) = -(x-1)(3x + 2)

Answer 8

First you need to find common factors.

Answer 9

sorry i am out of maths