How would I create a buffer with a pH of 3.10, but I can only use 1L of total solution.?

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How would I create a buffer with a pH of 3.10, but I can only use 1L of total solution.?

2007-04-22 20:28:52 · 2 answers · asked by T_dizzler 1 in Science & Mathematics ➔ Chemistry

2 answers

pH = pK + log [salt]/[acid]

if the buffer would be CH3COOH/CH3COO-

Ka =1.8 x 10^-5

pK = 4.74

3.10 = 4.74 + log [ CH3COO-] / [ CH3COOH]

- 1.64 = log [CH3COO-]/ [CH3COOH]

[CH3COO-] /[CH3COOH] = 0.0223

the ratio between salt and acid is 0.0223

we can take CH3COO- = 0.00223 M and CH3COOH =0.1 M

2007-04-23 02:22:47 · answer #1 · answered by Anonymous · 0⤊ 0⤋

Use a salt/base or salt/acid mixture.

2007-04-23 02:16:17 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 0⤋