Imagine that 0.5g of each carbonate was reacted with an excess amount of HCl. How much CO2 (g) should have bee

Question

n produced in each carbonate reaction? (show work)

Reaction #1- 0.5 g NH4HCO3=_____ g CO2

Reaction #2- 0.5 g NaHCO3=_______ g CO2

Reaction #3- 0.5 g KHCO3=________ g CO2

also what type of yield did you find in this problem? stoichiometry

Answer 1

All bases show the reaction

MHCO3 + HCl -> MCl + H2O + CO2

where M is the cation

Molar mass of NH4HCO3 = 79 g

Molar Mass of NaHCO3 = 84 g

Molar mass of KHCO3 = 100 g

Thus

Reaction #1- 0.5 g NH4HCO3=0.278 g CO2

Reaction #2- 0.5 g NaHCO3 = 0.262 g CO2

Reaction #3- 0.5 g KHCO3=0.22 g CO2