how to find the volume of a room given, a)stop clock b)small thread c)piece of stone.?

Answer 1

take the thread and drop the stone at the string's height to the ground. measure the speed at which the stone falls using the stop watch. knowing that we are located on planet earth, you can measure the lenght of the string using mathematical equations involving velocity and gravitational acceleration. Using the lenght of th string, measure the 3 sides of the room (height, width, length) and multiply them together.

hope that makes sense :)

for the person who answered before me....how can you reach the ceiling without any other materials? what if the SMALL thread isn't that long? and with what will you hang it to the ceiling?
i'm just thinking....quite and interesting question though :)

Answer 2

Time the fall of your stone from the ceiling to the floor. H = 1/2 gt^2; where H is the height of the ceiling, g = 32.2 ft/sec^2, and t = the sec of the timed fall. Find how long the piece of string is in feet, where l = H/n; and H in feet is the ceiling height, n is the number of times the length of string is laid end to end over the height, and l = is the length of the string segment. Using the string of known length l, measure out how many times the string length goes across the width (W) of the room and again along its length (L). This will give you the width and length in feet and fraction of feet. Then the volume is trivial as V = H X W X L in cubic feet.

EXAMPLE: You time the fall of the stone t = 1 sec. Then H = 1/2 32 (1)^2 ~ 16 feet. Walking the string length up the wall from the floor to the ceiling take 8 = n lengths; so that l = H/n = 2 feet per string length = 16/8. We presume you can reach the ceiling with some sort of extender (like a ladder or a pile of boxes).

Now measure end to end the room width using the string; you find m = 10.5 lengths; so W = m X 2 feet/length = 10.5 X 2 = 21 feet. Similary, measure the length of the room and that takes 21.3 string lengths = p; so that L = p X l = 21.3 X 2 = 42.6 feet.

Volume V = H X W X L = 16 X 21 X 42.6, whatever that turns out to be for this example.

NOTE: This method does not presuppose a cubic room. In the example, the three dimensions were not equal to each other.

Answer 3

One could make a pendulum using the thread and the stone, use the stop clock to measure the period of the pendulum, calculate the length of the pendulum from it's period (sorry, I don't know the formula, one could look it up) then use the thread to measure the room in steps. if the dimensions do not happen to be a multiple of your first thread length, you could adjust the pendulum to the remaining distance and determine it length again with the stop clock. Once you have the dimensions, you multiply width times length time height to get the volume.

Answer 4

Hang piece of stone from the roof such that it nearly touches the floor.

Disturb it slightly and note the time required for say, 20 oscillations. From the time period of the pendulam, you can know the height of the room.
time period = 1/(2 pi) * sqrt (l /g)
pi =3.1416
g = 9.81 m/sec^2
This is the length of the room.

Now you can measure other dimensions using this thread. Suppose the thread is 6 m long, then one third is 2 m and so.

Calculate the volume by l x b x h.

Answer 5

It is possible only if the room is in cube shape .
Hang the stone upto the ground (just it near to touch ground)with the thread from the sealing of roof.
Use this as pendulum and find it's time period with stop watch.
Use formula T = 1/2pie{squrt(l/g)}. Find length length of string that is one side of the room. volume of room is l*l*l cube unit.