A rectangular garden is to be surrounded by a walkway of constant width. The garden’s dimensions are 30 ft by 40 ft. The total area, garden plus walkway, is to be 1800 ft2. What must be the width of the walkway to the nearest thousandth?
2007-04-22 18:24:08 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
30*40=1200, so the area of the surrounding walkway is 600. The area of the walkway is: 2(40+2x)*x +2(30)x=600
(80+4x)x+60x=600 80x+4x^2+60x=600
so 4x^2+140x-600=0
so x^2+35x-150=0
x=3.86 ft the width of the drive way.
2007-04-22 18:38:41 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋
find out the garden area and subtract that from 1800 what you have is the area in ft2 of the walkway just figure it out from that it shouldnt be hard
2007-04-22 18:28:15 · answer #2 · answered by Chris W 4 · 0⤊ 0⤋
30 = -16t^2 + 32t + 50 -16t^2 + 32t + 20 = 0 divide by employing 4 -4t^2 + 8t + 5 = 0 t = ((-8 +/- sqrt(sixty 4-4(-4)(5))/-8 t = ((-8 +/- sqrt(a hundred and forty four))/-8 = (-8 +/- 12)/-8 t = -20/-8 = 2.5 seconds the different answer, t = -a million/2 2nd, represents the theoretical time while the article could have been at 30 feet on the way up. At t = 2.5 seconds, the article is on its way down. It reaches its maximum top at t = a million 2nd, while it reached sixty six feet.
2016-10-13 06:08:06 · answer #3 · answered by ? 4 · 0⤊ 0⤋