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i have to graph these
1.)y=9
2.)2x-3y=6

2007-04-22 18:13:53 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

1) This is just a horizontal line going through the point (0,9).
2) This line goes through the points (0,-2) and (3,0): just connect these two points to make your line.

2007-04-22 18:17:40 · answer #1 · answered by bruinfan 7 · 0 0

1. y=9 is a straight horizontal line at +9 on the y-axis

2. For 2x-3y=6, change it to y=.....To do so:
add 3y to both sides 2x=6+3y
subtract 6 from both sides 2x-6=3y
divide both sides by 3 (1/3)x-2=y
an easy way to graph this is to find any two points and then connect them with a straight line....Take x=0, then y=-2
you can also take x=3, then y=-1

You can use any x or y values in the equation to get these points, but x=0, and x=3 make sfor some easy values of y to plot of the graph. I hope this helped

2007-04-23 01:26:51 · answer #2 · answered by Anonymous · 0 0

y = 6 no matter the value of x, i.e. a horizontal line extending to infinity both sides

2x - 3y = 6
2x-6=3y
2/3x-2 = y
Substitute the values of x to find y and use the coordinates (x,y) to graph the cartesian plane

2007-04-23 01:19:52 · answer #3 · answered by Kuan T 2 · 0 0

1.)The graph is parallel to the x-axis at the point y=9
2.) point A(X=0,Y= -2) and point B(X=3,Y=0) ,and the slope is m=2/3 ,,,,,,,y=2/3 x -2 ,,,,,,,

2007-04-23 01:23:20 · answer #4 · answered by Tuncay U 6 · 0 0

First one is just a line, pretty simple. Horizontal line.

Second one, move the equation around so it become Y = .... and then graph from there. You plug in values for x if you're not sure.

2007-04-23 01:18:29 · answer #5 · answered by EMK 3 · 0 0

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