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3 answers

1.00 mol H20 @ 0°C ≈ 18 ml
1.00 mol H20 vapor @ STP ≈ 22.4 L

2007-04-22 18:06:11 · answer #1 · answered by Helmut 7 · 1 0

Err, you question is confusing.
You should use the Ideal Gas Law, which makes it 22.4L per mol at STP I think.
The liquid water part confuses me because the question is phrased in a misleading way. I would personally put 4 degrees C because that it the temperature where water is densest.

2007-04-23 01:08:20 · answer #2 · answered by advgrsbsdace 2 · 0 0

Volme of 100^0 celcius=is dt(v0)=10^2 v0^0celcius

2007-04-23 01:01:54 · answer #3 · answered by Faisal R 3 · 0 0

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