The barium sulfate precipitate is filtered and redissolved in hot water. The barium is then titrated with 0.1567 M EDTA. If it takes 12.66 mLs of EDTA solution to reach the endpoint, what was the concentration of the sulfate in the original 25.00 mL sample?
2007-04-22 17:48:31 · 2 answers · asked by jalabala6 1 in Science & Mathematics ➔ Chemistry
Moles of Ba2+ as sulphate = 2*(12.66x0.1567) millimol = conc. of SO4(2-) ions in 25 ml sample.
which is 3.968 millimol.
2007-04-23 02:16:43 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋
Nitric acid is NNO3 Silver is Ag and Silver nitrate is HNO3. Calculate the form of moles of Ag in 10 grams of 0.999 silver. Calculate how many moles of NO3 are in a hundred mL of fifty 3% nitric acid (i'm enormously specific you have far extra nitrate than you have silver yet you're able to desire to earnings). which each moles are restricting, the silver or the nitrate set the optimal form of moles of AgNO3 you're able to have, That restricting form of moles in a hundred mL answer instruments the concentration (eg. 10x the form of moles).
2016-11-26 21:56:56 · answer #2 · answered by ? 4 · 0⤊ 0⤋