Imagine that 0.5g of each carbonate was reacted with an excess amount of HCl. How much CO2 (g) should have bee

Question

n produced in each carbonate reaction? (show work)

Reaction #1- 0.5 g NH4HCO3=_____ g CO2

Reaction #2- 0.5 g NaHCO3=_______ g CO2

Reaction #3- 0.5 g KHCO3=________ g CO2

also what type of yield did you find in this problem? stoichiometry

Answer 1

In each case, one mole of the carbonate will produce one mole of CO2. Compute the no of moles in 0.5g of each carbonate (look up the molec. mass of each compound and divide that into 0.5g). That will be the no of moles of CO2, multiply it by the molec. mass of CO2 to get grams of CO2.

Divide the grams of CO2 by grams of carbonate to get yield (mult. by 100 to get % yield).