...the remaining rectangle
a] 5 in^2
b}85in^2
c]115in^2
d}150in ^2
2007-04-22 17:36:09 · 4 answers · asked by koalabear 2 in Science & Mathematics ➔ Mathematics
b}85in^2
The area to be removed = 5 X 3 =15
The area of the piece of paper = 10 x 10 = 100
100 - 15 = 85sq in
The only thing is that I don't think the remaining area would still be able to be considered a rectangle.
2007-04-22 17:39:52 · answer #1 · answered by BP 7 · 0⤊ 0⤋
B
10in * 10in = 100 in^2 which is the total area of the paper. Now subtract the area that was removed
5in * 3in = 15in^2
100in^2 - 15in^2 = 85in^2
Hope this helps!
2007-04-22 17:42:26 · answer #2 · answered by HP 2 · 0⤊ 0⤋
5 * 3 = 15
10^2 = 100
100 - 15 = 85
ANS : B.
2007-04-22 19:01:10 · answer #3 · answered by Sherman81 6 · 0⤊ 0⤋
Man, I wish Yahoo!Answers were around when I was a kid so that people could do my homework for me....
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2007-04-22 17:44:15 · answer #4 · answered by Frank 6 · 0⤊ 0⤋