Equilibrium Rotation Physics . Very Confused?

Question

A door has a height of 2.1 m along a y axis that extends vertically upward and a width of 0.99 m along an x axis that extends outward from the hinged edge of the door. A hinge 0.30 m from the top a hinge 0.30 m from the bottom each support half the door's mass which is 23 kg.

What is force on door at top hinge?
(N i + Nj)???

What is force on door at bottom hinge?
(Ni + Nj)

your work looks trustworthy, but the answer is being rejected

Answer 1

The two hinges will share the vertical component of the weight of the door equally, or
23*9.81/2 N = 112.815 N
Taking the moment about the bottom hinge,
F*(2.1 - 0.6) = 23*9.81*0.99/2
F = 23*9.81*0.99/(2*1.5)
F = 74.4579 N pulling on the door at the top hinge.
Taking the moment about the top hinge,
F = 74.4579 N pushing on the door at the bottom hinge.
If i is the vertical vector , positive up, and
j is the horizontal vector, positive toward the door,
F(top) = 112.815 i - 74.4579 j
F(bottom) = 112.815 i + 74.4579 j