4x+2y=0
8x+4y=9
i got no solution as my answer..
2007-04-22 15:58:55 · 6 answers · asked by fishingforhope 1 in Science & Mathematics ➔ Mathematics
thankyou so much
2007-04-22 16:05:13 · update #1
There is no solution for the question. There is no unique value of x and y which will staisfy both equations.
2007-04-22 16:04:15 · answer #1 · answered by Daniel T 2 · 0⤊ 0⤋
Correct. Double the first equation:
4x+2y=0
2(4x+2y)=2(0)
8x+4y=0
But 8x+4y=9, so 0=9. There is no solution. These are parallel line with no intersection.
2007-04-22 16:03:41 · answer #2 · answered by novangelis 7 · 0⤊ 0⤋
You can see from looking at these that the second equation is twice the first one. But, they equal different amounts that are not twice (0 and 9)
There is no solution.
2007-04-22 16:03:43 · answer #3 · answered by ignoramus 7 · 0⤊ 0⤋
multiply the top one by -2
so itd be -8x+2y=0
8x+4y=9
then that would cancel the x's so 6y=9 blah blah blah
good luck
2007-04-22 16:04:53 · answer #4 · answered by Dylan 2 · 0⤊ 0⤋
Correct. No solution.
The two lines are parallel.
2007-04-22 16:02:58 · answer #5 · answered by Steve A 7 · 0⤊ 0⤋
you are correct - there is no solution
2007-04-22 16:03:13 · answer #6 · answered by coldb00t 1 · 0⤊ 0⤋