You're missing a piece of information. concentration of KOH. Concentration can be expressed in molarity, molality, weight %, etc and should have been defined in the problem.
if you're given molarity, ie moles/liter (?? moles / L) below, solve it like this....
2.34 ml x (1 L/1000 ml) x (?? moles / L) x (10^6 micromoles / mole) = X micromoles.....
2007-04-23 01:52:52
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answer #1
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answered by Dr W 7
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You need the concentration of the KOH. This will probably be given in M, short for molarity, or N, short for normality. Both of these units are moles per liter, which is the same thing as millimoles per milliliter. There are a thousand micromoles in a millimole, so multiply the M or N of your solution by 1000, then multiply that by the volume to get the number of micromoles.
2007-04-22 22:57:28
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answer #2
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answered by Amy F 5
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Buy a shrinking machine, and put the KOH through it. Actually, you dont have enough info to do your operation. You need to know the concentration of KOH in your solution. For instance, if the KOH was 0.01 M, one liter of the solution would have 10^-2 moles, but since you have 2.34 mL, you have 2.34x10^-5 moles of KOH. A micromole is 1x10^-6 moles, so even at this level you have 23.4 micromoles. That's how you do it, but get your act together first.
2007-04-22 22:59:26
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answer #3
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answered by cattbarf 7
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