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The probability of three queens, two kings is 4/52 * 3/51 * 2/50 * 4/49 * 3/48 * 10 (number of possible ways to do it).
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4/52 * 3/51 * 2/50 * 4/49 * 3/48 * 10 = 1/108290

2007-04-22 15:55:08 · answer #1 · answered by Steve A 7 · 0 0

4C1*4C2*5C2/52C5 = 0.000092345

2007-04-22 16:12:40 · answer #2 · answered by Helmut 7 · 0 0

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