math help plz!?

Question

1. Two mice are racing around the edges of a square whose sides are 2 feet in length. They start at the same vertex and both go in a clockwise directiom. One mouse travels at a constant rate of 1 foot per second and the second mouse travels at a constant rate of 2 ft per second. After 22 seconds, how far apart will the mice be from each other?

2. The volume of box A is 50% greater than the volume of box C. The volume of box B is 25% greater than the volume of box C. Therefore, the volume of box A is what precent greater than the volume of box B?

How would I solve these??

Answer 1

1. Let the starting vertex be A of square ABCD.
The perimeter of the square is 8'.
After 22 seconds, the first mouse have gone around the square twice (16') and will be at vertex D (6 feet from the beginning).
After 22 seconds, the second mouse will have gone 44', which is five times around the square (40')and half-way again, so that mouse will be at vertex C (4' from the beginning).
The two mice will be (6-4 = 2) two feet apart.

2. A = 1.5C
B = 1.25 C
(A-B)/B = (1.5C - 1.25C)/1.25C = .25/1.25 = .2 or 20%