Two cards are drawn, one from each of two decks. Find the probability of A) 2 Kings B) At least one club C) not more than 1 red card
2007-04-22 15:07:28 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
A) 4/52 x 4/52 = 16/2704 or 1/169
B) 1/4 x 1/4 = 2/16 or 1/8
C) sorry dont know
2007-04-22 15:12:23 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Since you only have a two-card draw, there really isn't much binomial probability involved.
For (a), the probability of one king from either deck is 1/13. Thus the probability of 2 successful draws is (1/13)^2 of 1/169.
For (b), the probability of one club from either deck is 1/4. Since this is an "at least" question, we don't worry about the two club draw, and the answer is 1/4
For (c), the probability of a red card from either deck is 1/2. Since this is "not more", we can compute the probability (two red draws) and subtract that from 1. The two red draw prob. is 1/4, so the probability of (0 or 1 red card) is 3/4
2007-04-22 15:15:41 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
4/52*4/52
b. find no clubs
3/4*3/4
then 1- 0.5625=0.4375
c. 1/2*1=1/2
2007-04-22 15:13:03 · answer #3 · answered by leo 6 · 0⤊ 0⤋