A 100mL sample of 0.200 M aqueous hydrochloric acid is added to 100mL of 0.200 M aqueous ammonia in a calorimeter whose heat capacity is zero. The following reaction occurs when the two solutions are mixed. [Assume that the density of the resulting solution is that of pure water].
HCl (aq) + NH3 --> NH4Cl (aq)
The temperature increase is 2.34 Celsius. Calculate delta H per mole of HCl and NH3 reacted.
2007-04-22 14:25:10 · 2 answers · asked by ahsuog 1 in Science & Mathematics ➔ Chemistry
Use q = m x c x delta T.
m = 200g (or 0.2kg). delta T = -2.34.
c = 4.18.
Then divide the answer by 0.02 - the number of moles of either chemical.
2007-04-22 19:43:50 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋
Why forty 4 thumbs down for SciMann? it is in subject-loose words suitable answer for the period of this tread. The values of delta H of formation given are all incorrect and don't make any sence. Why would formation of CH4 be endothermic? Why would formation of O2 require any skill? the climate of their trouble-free states have enthalpies of formation equivalent 0 by making use of skill of definition.
2016-12-26 20:02:43 · answer #2 · answered by scelfo 3 · 0⤊ 0⤋