how do i solve sin(x)tan(x)=sin(x)?

Answer 1

Here is what you don't do. You don't cancel the sinx like the previous answerer.

sinx*(tanx - 1) = 0.
This is true when sinx = 0 and when tanx = 1
x = 0, 45, 180, 225, 360 and so on.

That's it.

Answer 2

make it sin(x)tan(x)-sin(x)=0 and put it into your graph set the window to x 0-360 and y from -1 to 1. record through every x intercept which should be at 0 45 180 225 and 360

Answer 3

There are 2 solutions. One is sin(x) = 0, since then both sides of the equation equal zero. That corresponds to angles that are integer multiples of 180 degrees (including zero).

The nonzero solution is obtained by dividing both sides of the equation by sin(x). In that case you get tan(x) = 1, which is a 45 degree angle.

Answer 4

The answer is x=45 degrees or pi over 4. Divide both sides by sin(x) giving you tan(x)=1. Since tan=sin/cos, then this becomes sin(x)=cos(x) so the answer can only be 45 degrees. (unless you count x=0)

Answer 5

Divide both sides by sin(x).
tan(x)=1
x=tan^-1(1)
x=pi/4