MATH HELP-->trig expressions?

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MATH HELP-->trig expressions?

I can't figure out this problem. any help would be appreciated!

the expression sinx(cotx-cscx) is equivalent to...
a)cosx-sin²
b)2cosx
c)-sinx
d)cosx-1

2007-04-22 14:12:44 · 2 answers · asked by Anonymous in Education & Reference ➔ Homework Help

2 answers

SinX(CotX-CscX)

since CotX= Cox X/SinX and CscX=1/Sinx

Then
SinX((CosX/SinX)- (1/SinX))
SinX((CosX -1)/SinX

SinX cancels out and leaves
CosX-1

2007-04-22 14:29:38 · answer #1 · answered by Robert L 7 · 0⤊ 0⤋

d cosx-1

sinx (cot x - csc x)=

sinxcotx - sinxcscx =
(sinx)(cotx) = cosx
(sinx)(cscx) =1

=cosx -1

2007-04-22 21:33:37 · answer #2 · answered by knowinghimm 2 · 0⤊ 0⤋