Can someone help me calculate the mole Fraction of 3.21 g NaOH in 0.752 L H2O?
2007-04-22 13:30:57 · 3 answers · asked by Britt 2 in Science & Mathematics ➔ Chemistry
Molar mass of NaOH=40
So no. of moles = 3.21/40 =0.08025~0.08
Molar mass of water = 18
.752 L=752 g (1 L= 1000 g in case of water)
No.of moles of water=752/18=41.77~41.80
Total no. of moles=41.80 + 0.08 =41.88
So mole fraction of NaOH = 0.08/41.88 = 0.0019102~0.002
2007-04-22 21:24:57 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The two numbers of moles are 3.21/40 and 752/18. Add them together, and work out what fraction the NaOH is of the whole.
2007-04-23 02:40:42 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋
weight of 1 mol of NaOH is 40 gm.
therefore 3.21 gm means 3.21/40 moles=.08025 moles
18L means i mole of water
therefore .752L means .752/18=.042 moles
total number of moles in the solution is .08025 + .042=.122 moles
mole fraction ofNaOH is .08025/.122 *100 =65.76%
2007-04-24 15:03:23 · answer #3 · answered by K R 2 · 0⤊ 0⤋