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Barium chloride + Sodium carbonate
a.) name of precipate = Barium carbonate
b.) ion equation for precipitate formed = BaCO3
c.) ion equation for original solutions = BaCl2
d.) ion equation for new solution.... okay this is where i get stuck. the answer is: NaCl, but I don't get how they got that from all of the above... are they putting Sodium & the chloride from the original solutions together??

and how would you do this next one?

Barium chloride + Magnesium sulfate
a.) write name of precipitate formed.
b.) write ion equation for the precipitate formed.
c.) write ion equation forthe original solutions.
d.) write ion equation forthe new solution.
e.) write the name of the new solution.

thanks for all your help. i really don't get this stuff.

2007-04-22 13:17:12 · 2 answers · asked by ok buddy 2 in Science & Mathematics Chemistry

2 answers

BaCl2(aq) + Na2CO3(aq) ===> BaCO3 + 2NaCl

The "ion equation" for the new solution is 2Na+ + 2Cl-, but I don't know how you're to know that one.

a) Barium sulfate
b) BaSO4
c) BaCl2
d) MgCl2
e) Magnesium chloride

2007-04-22 14:23:27 · answer #1 · answered by steve_geo1 7 · 1 0

BaCl2 + Na2 Co3........> BaCO3 + 2NaCl

BaCl2 + MgSO4.....> BaSO4 + MgCl2
The preciitate is BaSO4
rest you can do yourself and gain some knmowledge

2007-04-22 13:28:33 · answer #2 · answered by gangico 3 · 0 0

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