How do I found the slope and y-intercept of an equation?

Question

How do I found the slope and y-intercept of an equation? Such as stated: for the following: 5x+y=10, 2,y-12x= -18, and y= -2/3x +5

m=?

b=?

Answer 1

put the equations into slope intercept form y = mx + b
m = slope
y = y-intercept

5x+y=10,

subtract 5x for both sides
y = -5x + 10
m = -5
b = 10


y-12x= -18

add 12x for both sides
y = 12x - 18
m = 12
b = -18



y= -2/3x +5, this equation is already in the slope form
m = -2/3
b = 5

hope this helps

Answer 2

The first thing you need to do is rearrange the equations into the form y=mx +b (the equation of a straight line)

y = -2/3x +5 is already done so I will use that one to explain.

The -2/3 is the m part and the +5 is the b part. Therefore, the gradient or slope (m) is -2/3 and the y-intercept(b) is 5.

I will leave the other two for you to rearrange but here are a few hints. The second one will divide throughout by 2 after you have rearranged it (providing I am interpreting the question correctly as 2y -12x = -18) and be careful with your signs when you rearrange!

Answer 3

The equation of a straight line is
y=mx+b
Where m is the slope and b is the y intercept

5x+y=10 restated is y=-5x+10
From the definition of a straight line
m=-5, y intercept (b) is 10

2y-12x=-18 restated is
y-6x=-9 or
y=6x-9
m=6, b=-9

y= -(2/3)x+5
m= -2/3, b is 5