1. 9x^2-16=0
2. 100x^2-49=0
2007-04-22 09:49:29 · 4 answers · asked by Rhonda 2 in Science & Mathematics ➔ Mathematics
1) 9x² - 16 = 0
Take 16 over to the RHS than take square roots of both sides
9x² = 16
3x = ± 4
(± is very important, because 4²=16, but (-4)²=16 as well!)
Now divide both sides by 3:
x = ± 4/3
i.e. x = 4/3, -4/3
2.) 100x² - 49 = 0
Proceed as before
100x² = 49
10x = ± 7
x = ± 7/10
i.e. x = 7/10, -7/10
Hope this helps.
P.S.: To the person below: Grow up!
2007-04-22 09:53:52 · answer #1 · answered by M 6 · 4⤊ 2⤋
1.
9x^2 = 16
x^2 = 16/9
x = +/- 4/3
2.
100x^2 = 49
x^2 = 49/100
x = +/- 7/10
2007-04-22 09:55:50 · answer #2 · answered by suesysgoddess 6 · 1⤊ 0⤋
9x² - 16 = 0
(3x - 4)(3x + 4) = 0
- - - - - - - -
100x² - 49 = 0
(10x - 7)(10x + 7)
- - - - - - - - - -s-
2007-04-22 10:44:40 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
take 16 and 49 on the other side of the equal to sign..and take under root on both sides... respectively for each question
BLAH!
2007-04-22 09:54:50 · answer #4 · answered by zo shirazi 1 · 0⤊ 3⤋