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Whats the aprox quantity of grams of aluminum needed to furnish 6.02 x 10^23 electrons in an electrolyte cell?

2007-04-22 09:41:42 · 1 answers · asked by Frankie L 1 in Science & Mathematics ➔ Chemistry

1 answers

1/3 of a mole of Al, so 27/3 = 9g

2007-04-25 06:30:19 · answer #1 · answered by Gervald F 7 · 0⤊ 0⤋

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