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If 200mL N2 at 25 degrees celcius and pressure 400mmHg, and 200mL O2 at 25 degrees celcius and pressure 300mmHg are placed in a vessel with volume 700mL, what is the total pressure of the mixture (in mmHG)?

2007-04-22 09:09:39 · 4 answers · asked by Frankie L 1 in Science & Mathematics Chemistry

Thank you!

2007-04-22 09:22:25 · update #1

4 answers

(p1xt1):v1 = (p2xt2):v2

p1 = pressure 1
v1 = volume 1
t = 1
p2 = pressure 2
v2 = volume 2
t2 = also 1

so do the math !

2007-04-22 09:16:47 · answer #1 · answered by peternaarstig 3 · 0 0

You first need to solve for how many moles of N2 and O2 you have. Use PV=nRT to do this. You should get 0.00430 moles N2 and 0.00323 moles O2. Add these together to get the n(total), which equals 0.00753 moles.
Use this n(total) value for the new volume to calculate the final pressure. Converting to mm Hg should give you 0.334 mmHg

2007-04-22 09:25:40 · answer #2 · answered by Anonymous · 0 0

One way would be to use the ideal gas law to calculate the moles of each gas in the two original samples. THen add the moles of the two gases together, and use the ideal gas law to calculate the pressure of the mixture.

2007-04-22 09:22:32 · answer #3 · answered by hcbiochem 7 · 0 0

200 mmHg

2007-04-22 09:18:05 · answer #4 · answered by Clint 3 · 0 0

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