math help!!!?

Question

how do you find what n equals if...
10v^2=13v+3
i know that u have to get zero on both sides but then do u factor it and then what?

Answer 1

Step by step procedure

Put the equation to standard form

10v = 13v + 3

Transposing - 13v on both sides of the equation

10v - 13v = 13v + 3 - 13v

10v - 13v = 3

Transposint - 3 on both sides of the equation

10v - 13v - 3 = 3 - 3

10v - 13v - 3 = 0

The equation is in standard form and ready for factoring

The middle term is - 13v

Find the sum of the middle term

Multiply the firt term 10 by the last term 3 equals 30 and factor

factor of 30

1 x 30
2 x 15. . .<=. .use these factors
3 x 10
5 x 6

+ 2 and - 15 satisfy the sum of the middle term

insert + 2v and - 15v into the equation

10v - 13v - 3 = 0

Factor by grouping

10v + 2v - 15v - 3 = 0

2v(5v + 1) - 3(5v + 1) = 0

(2v - 3)(5v + 1). . .These are your factors

- - - - - - - -

Roots

2v - 3 = 0

2v - 3 + 3 = 0 + 3

2v = 3

2v / 2 = 3/2

v = 3/2

- - - - - - - -

Roots

5v + 1 = 0

5v + 1 - 1 = 0 - 1

5v = - 1

5v / 5 = - 1 / 5

v = - 1 / 5

- - - - - - - - - -s-

Answer 2

10v^2=13v+3
umm not sure what your asking
but subtract 13v and subtract 3 from both sides
10v^2-13v-3=0
nowfor factoring
remember standard form is ax^2+bx+c=0
a = 2,5
1,10

c = 1,-3
-1,3
3,-1
-3,1

so now we consider all possible factor combinationsswitching v for x, just habit)

(2x+1)(5x-3)
(2x-1)(5x+3)
(2x+3)(5x-1)
(2x-3)(5x+1)
(x+1)(10x-3)
(x-1)(10x+3)
(x+3)(10x-1)
(x-3)(10x+1)
ok to check and see which one is the correct factor, we multiply them all out with foil, but if you did that they will all produce the a and c term being 10x^2 and -3 respectivaly, only the b term will be different in all the cases with one being the correct term
so what i do is a modification of foil namely OI i just multiply the outer terms and the inner terms and add them whichever one generates -13x is the correct factor


(2x+1)(5x-3)=-6x+5x=-x
(2x-1)(5x+3)=6x-5x=x
(2x+3)(5x-1)=-2x+15x=13x
(2x-3)(5x+1)=2x-15x=-13x
(x+1)(10x-3)=
(x-1)(10x+3)=
(x+3)(10x-1)=
(x-3)(10x+1)=

once you find the answer no sense in working the rest
so our factor is (2x-3)(5x+1)

now the orginal problem was set equal to 0
so (2x-3)(5x+1)=0
now use the zero product property and set each factor =0
2x-3=0 , 5x+1=0 and solve for x
2x=3 , 5x=-1
x=3/2 , x=-1/5

fin

Answer 3

You get
10v²-13v-3 = 0.
Now factor:
(2v-3)(5v+1)=0.
Set each factor to 0 and solve:
v = 3/2
or
v = -1/5.

Answer 4

10v^2=13v+3
10v^2-13v-3=0
(5v+1)(2v-3) = 0

v = -1/5, 3/2

Answer 5

what v equals if 10v^2=13v+3

10v^2-13v-3=0

you may use quadratic formula
or factor it

(v-1)(v-3/10)=0

v1=1

v2=3/10

Answer 6

10v²=13v+3
10v²-13v-3=0
(5v+1)(2v -3)=0
v=-1/5 or 3/2

Answer 7

10v^2=13v+3
set equal to zero
10v^2-13v-3=0
use [-b +/- sqrt(b^2-4ac)]/2a to find the roots
where a=the coefficient associated w/ v^2 (here it is 10)
a=10, b=-13, c=-3
so roots are 1.5 and -0.2

Answer 8

10n² - 13n - 3 = 0
(5n + 1).(2n - 3) = 0
(5n + 1) = 0 gives n = - 1/5
(2n - 3) = 0 gives n = 3 / 2
Solutions are n = - 1 / 5 , n = 3 / 2

Answer 9

just so u kno.. there is no n there is only a v