The length of one of the equal legs of an isosceles triangle is 3 inches more than 2 times the length of the?

Question

The length of one of the equal legs of an isosceles triangle is 3 inches more than 2 times the length of the base. If the perimeter is 31 in, find the length of one of the equal legs.

Answer 1

let length of equal sides be x
other side = y
x = 2y + 3
31 = (2y + 3) + (2y + 3) + y
31 = 5y + 6
5y = 25
y = 5
x = 13
length of one of equal legs = 13"

Answer 2

the length of the equal sides are 13 and the base is 5. if you want me to show you the work i can just ask