How many digits will the number 6^(712) have , given log 6 =0.778 ?
How do i go about it
please explain . please explain ..dont just give the solution .
i dont understand how can co-relate logirithm with number of digits .
If you have a solution , please explain the steps why are doing that way .
well, let me start this way say Z=6^(712)
taking log , log z=712 log 6
does it mean something ? no , i dont think ...i cant corelate this logirithim with the number of digits in the final outcome number.
If anybody have solution , please let me know.
Thank you
2007-04-22 06:52:28 · 2 answers · asked by sanko 1 in Science & Mathematics ➔ Mathematics
log z=712 log 6 is true.
log z=712*0,778
logz=553,936
10^553,936=z
554 digits
2007-04-22 07:00:05 · answer #1 · answered by iyiogrenci 6 · 0⤊ 1⤋
log base 10 gives you the number of digits.
log z= 712 log 6 = 712 * 0.778 = 553.936
So the number has 553 digits.
2007-04-22 13:59:05 · answer #2 · answered by Demiurge42 7 · 0⤊ 0⤋