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y=x^3-13x^2+36x
and
y=-x^3+13x^2-36x

2007-04-22 06:46:28 · 1 answers · asked by kaitie 1 in Science & Mathematics Mathematics

1 answers

y1=y2
x^3-13x^2+36x=-x^3+13x^2-36x
2x^3-26x^2+72=0
2x(x^2-13x+36)=0
x1=0
x2=4
x3=9

draw the figures of y1 and y2

take integral

2007-04-22 06:55:14 · answer #1 · answered by iyiogrenci 6 · 0 0

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