2007-04-22 06:26:01 · 5 answers · asked by amyslittleworld 1 in Science & Mathematics ➔ Mathematics
2x+15=41
x=13
2007-04-22 06:33:29 · answer #1 · answered by malasunas 3 · 0⤊ 0⤋
let x be that number
"sum of 15 and twice a number is 41"
means take 2 multiply it by our number x and add 15 and you should get 41.. This can be represented by this equation:
2x+15=41
Now, just solve for x
2x+15 = 41 subtract 15 from both sides
2x=26 divide by 2
x=13
2007-04-22 13:29:09 · answer #2 · answered by radne0 5 · 2⤊ 0⤋
15 + 2x = 41
2x = 41 - 15 = 26
x = 26/2 = 13
2007-04-22 13:29:36 · answer #3 · answered by S. B. 6 · 0⤊ 0⤋
let number be x
2x + 15 = 41
2x = 26
x = 13
Check
15 + (2 x 13) = 15 + 26 = 41 as required
2007-04-22 13:36:08 · answer #4 · answered by Como 7 · 0⤊ 0⤋
15+2x = 41
2x= (41-15) =26
So, x = 26/2 = 13.
2007-04-22 13:36:34 · answer #5 · answered by Dhiraj 2 · 0⤊ 0⤋