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tanh(-x)=-tanh x

2007-04-22 06:01:46 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

By definition

tanh(x) = [e^x - e^(-x)] / [e^x + e^(-x)]
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For the problem at hand we have

tanh(-x) = [e^(-x) - e^(- -x)] / [e^(-x) + e^(- -x)]

= [e^(-x) - e^x] / [e^(-x) + e^x]

= - [e^x - e^(-x)] / [e^x + e^(-x)] = - tanh(x)

2007-04-23 22:48:39 · answer #1 · answered by Northstar 7 · 0 0

I did hyperbolics a few months ago so I am alitte rusty but I do believe that the equation for tanh(x)= e^x - e^-x/ e^x + e^-x correct? So if you put any negative number inside of that equation, you will get a negative solution. So if you have to prove that equation, draw a graph (which should be in your book or just search tanh (X)) and then put in a negative number.

2007-04-22 06:15:45 · answer #2 · answered by ritcheybaby19 2 · 0 0

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2016-12-26 19:26:24 · answer #3 · answered by ? 3 · 0 0

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