help thanks physics question?

Question

A diving board of length L = 3.00 is supported at a point a distance 1.00 m from the end, and a diver weighing 550 Nstands at the free end . The diving board is of uniform cross section and weighs 280 .N

1) Find the force at the support point.

2) Find the force at the end that is held down.

Answer 1

Summation of forces = 0 = W1+W2 -S1 +S2
Summation of moments about the pivot point = 0 R1W1+R2W2 - R3S1- R4 S2=0
R3S1 (since it is a pivot point)
R1= 2.0 m
R2= 0.5m =(1.5 - 1.0)
R4= 1.0m
R1W1+R2W2 -R4 S2=0
S2=(R1W1+R2W2 -)/r4
S2=(2 x 550 + 0.5 x 280)/1.0=1240N (the force at the end that is held down)

and since

0 = W1+W2 -S1 +S2
S1= W1+W2 +S2 = 550 + 280 + 1240 = 2070 N (force at the support point)