how many real solutions are there for x^2 + ax + b = 4
2007-04-22 05:23:10 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
the answer is not infinite solutions, and i do not know how to do this...
2007-04-22 05:55:08 · update #1
It depends on the values for a and b...
if the discriminant (the square root of b^2-4ac) in the quadratic formula is greater than 0, you have two real solutions.
if it is equal to zero, you have one real solution...
if it's less than zero, you have imaginary roots...
hope it helps...
2007-04-22 05:28:25 · answer #1 · answered by YK 2 · 0⤊ 0⤋
x^2 + ax + b = 4
x^2 + ax + b -4 = 0
a^2 > = 4(1)(b-4)
a^2>= 4b-16 gives real solutions
So for any b you pick you can always find an a such that a^2 => 4b - 16. So there is an infinite number of real solutions possible.
2007-04-22 12:37:57 · answer #2 · answered by ironduke8159 7 · 0⤊ 0⤋
find 3 pts.and draw parabola
2007-04-22 12:30:06 · answer #3 · answered by dwinbaycity 5 · 0⤊ 1⤋