f(x)=2-e^-x?

Question

differentiate: i think the answer is -e^-x, but im not sure

Answer 1

The derivative of e^u is e^u * du. du in this case is just -1.

f(x) = 2 - e^(-x)

f'(x) = 0 - e^(-x)(-1)
f'(x) = e^(-x)

The negatives from -1 and -e^(-x) cancel out leaving you positive e^(-x). You were close though =)

Answer 2

It is f´(x) = e^-x as per chain rule the derivative of e^-x =-e^-x