The intensity of light decreases as it passes through sea water. The equation ln(I0/I) = 0.014d relates the intensity of light I at the depth of d centimeters with the intensity of light I0 in the atmosphere. Find the depth of the water where the intensity of the light is half the intensity of the light in the atmosphere.
2007-04-22 02:00:02 · 2 answers · asked by yassem1ne 2 in Science & Mathematics ➔ Mathematics
Since the intesity of light is 10 in atmosphere and you want to find the depth when the intensity of light is half the intensity of lighjt in the atmospher, then L = 5 (half of 10)
So:
ln(10/5) = 0.014d
ln(2) = 0.014d
Divide by 0.014 to isolate d:
d = ln(2)/0.014
d = 49.51cms
2007-04-22 04:06:37 · answer #1 · answered by Rafael Mateo 4 · 0⤊ 0⤋
ln(Io/l=0.014d
Io/I= 2
so ln2=0.014d and d= ln2/0.014 =49.51cm
2007-04-22 09:20:17 · answer #2 · answered by santmann2002 7 · 0⤊ 0⤋