what is y=lnx/x^2?

Answer 1

It is a function with domain x>0
y´= 1/x^4( x-2x lnx)
y´=0
x=0 (can´t be)
1-2ln x=0 so lnx=1/2 and x = e^1/2
sign of the derivative
++++++e^1/2---------- so f(e^1/2 is a relative maximum)
f(e^1/2)= 1/2e
Range ( -infinity, 1/2e]

Answer 2

x/x = 1
1 to the 2nd power is 1
In1 = 0
Y = 0?