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In a balloon, how many grams mass will 1 cubic meter of hydrogen molecules lift?

2007-04-22 01:24:06 · 2 answers · asked by Maximillian 1 in Science & Mathematics Chemistry

2 answers

Lancenigo di Villorba (TV), Italy

I AGREE NOT THE PREVIOUS ANSWER.

Mr. Maussy forgiven that the balloon start from the Earth's Crust, e.g. near zero meter of altitude.
So, he had to refer to Pressure and Temperature conditions as 1 atm and 18 °C (e.g. mean value on an year).
In these repliable conditions, he had to apply the "Ideal Gas's law" in order to evaluate the AIR's DENSITY

p * V = n * R * T

that is

n / V = p / (R * T) = 1 / (0.0821 * 291) = 4.18E-2 mol/liter

Now, he had to remember that the balloon is rising, hence he had to understand that the gas (e.g. Pure Hydrogen) inside in the balloon cannot aggregate in a DENSITY VALUE GREATER THAN the surrounding air.
The CALCULATED AIR's DENSITY is THE GREATEST VALUE OF HYDROGEN's DENSITY.
Finally, the Hydrogen's Mass contained in the Unitary Volume

V * M.W. * n / V = 1,000 * 2.0 * 4.18E-2 = 83.7 g

ANY GREATER MASS IMPEACH TO BALLOON's RISING!!

I hope this could be clear.

2007-04-22 02:53:52 · answer #1 · answered by Zor Prime 7 · 0 0

Impossible to answer your question without knowing the temperature and pressure

I wiil try , I suppose the temperature is 0°C at atmospheric pressure

At that temperature the volume of a mole is 22.4L

1 m^3 =1000L
this corresponds to 44.64 moles
as 1 mole of hydrogen is 2g

so 44.64*2 = 93.28g

But I repeat this at0°c, 1atm!!!

2007-04-22 08:33:29 · answer #2 · answered by maussy 7 · 0 0

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