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Taking liquid octane as a model for conventional petroleum, Calculate ∆combG  /kJ mol-1 for the combustion of 1mole of octane, & then 1 litre of octane. the combustion reaction is;

C8H18 (l) + 12.5 O2 -----> 8 CO2 + 9 H20

2007-04-21 16:17:12 · 1 answers · asked by cat_ren_03 1 in Science & Mathematics Chemistry

∆fG/ kJ mol-1 = C8H18 = + 6.4
= CO2 = - 394
= H20 = - 237

density g/cm-3 = C8H18 = 0.698

molar mass g mol-1 = C8H18 = 114

2007-04-21 18:45:25 · update #1

data is written above!!!!!!!! 7 hours ago!!! :(

2007-04-22 01:57:24 · update #2

1 answers

Data ?????

2007-04-21 19:37:44 · answer #1 · answered by ag_iitkgp 7 · 0 0

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