Taking liquid octane as a model for conventional petroleum, Calculate ∆combG /kJ mol-1 for the combustion of 1mole of octane, & then 1 litre of octane. the combustion reaction is;
C8H18 (l) + 12.5 O2 -----> 8 CO2 + 9 H20
2007-04-21
16:17:12
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1 answers
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asked by
cat_ren_03
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in
Science & Mathematics
➔ Chemistry
∆fG/ kJ mol-1 = C8H18 = + 6.4
= CO2 = - 394
= H20 = - 237
density g/cm-3 = C8H18 = 0.698
molar mass g mol-1 = C8H18 = 114
2007-04-21
18:45:25 ·
update #1
data is written above!!!!!!!! 7 hours ago!!! :(
2007-04-22
01:57:24 ·
update #2