A rotating beacon is located 15ft from a wall. If the distance from the beacon to the point on the wall?

Question

is aimed is given by a=15 absolute value of sec2(pie)t, where t is in seconds, find a when t= 0.44

Answer 1

It makes sense that a constant-speed rotation of a ray at a fixed distance from a wall is the secant (1/cosine) of the angle theta that the ray makes with the distance measurement line, since the measurement line forms a right angle with the wall, the measurement line is the adjacent side with respect to theta, and the distance from beacon to ray intercept with the wall is the hypotenuse. If theta = 2*pi*t and t is in seconds, the beacon rotates at 1 rev/sec.
Anyway, the answer is:
Theta = 2 * pi * 0.44 = 2.765 rad.
15 * abs(secant(Theta)) = 16.13 ft