[ 1-(2-a)-{3-(a-a2)}-a-(a2-a3)]
Solution
=[1-2+a-{3-a+a2}-a-a2+a3]
=[1-2+a-3+a-a2-a-a2+a3]
=(1-2-3)+(a+a-a)+(-a2-a2)+a3
=-4+a-2a2+a3 or a3-2a2+a-4
here a2 means a square
nd a3 means a cube
tell me is it correct solution?
2007-04-20 22:50:28 · 5 answers · asked by sara_82 1 in Science & Mathematics ➔ Mathematics
yup.. it's correct.. :)
2007-04-20 22:58:11 · answer #1 · answered by Yssa A 3 · 0⤊ 0⤋
Question: [1-(2-a)-{3-(a-a2)}-a-(a2-a3)]
Solution:
= [1-2+a -{3-a+a2} -a-a2+a3]
= [ 1-2+a-3+a-a2-a-a2+a3]
= 1-2-3 +a+a-a -a2-a2 +a3
= -4 +a -2a2 +a3
2007-04-21 06:12:57 · answer #2 · answered by in_sudhir 1 · 0⤊ 0⤋
= 1 - 2 + a - 3 + a - a² - a - a² + a³
= a³ - 2a² + a - 4
Which agrees with your solution.
2007-04-21 05:58:24 · answer #3 · answered by Como 7 · 0⤊ 0⤋
It is correct
2007-04-21 08:38:17 · answer #4 · answered by durriyaa 2 · 0⤊ 0⤋
yo.......... it's absolutely right :)
2007-04-21 06:09:28 · answer #5 · answered by Vishwarun 2 · 0⤊ 0⤋