Find the vertex of the parabola y = 6x squared + 3x + 1 by completing the square.?

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Find the vertex of the parabola y = 6x squared + 3x + 1 by completing the square.?

2007-04-20 22:12:55 · 3 answers · asked by Fang-Lei M 1 in Science & Mathematics ➔ Mathematics

3 answers

6x^2 + 3x + 1
6(x^2 + 1/2 x) + 1
6(x^2 + 1/2 x + 1/16) + 1 - 6(1/16)
6(x + 1/4)^2 + 5/8

So.....
Vertex is (- 1/4, 5/8)

2007-04-20 22:48:16 · answer #1 · answered by Mathematica 7 · 1⤊ 1⤋

y = 6xÂ² + 3x + 1
y = 6.[xÂ² + (1 / 2).x + 1 / 6 ]
y = 6.[( xÂ² + (1/2).x + (1/4) - (1/4))+ (1/6) ]
y = 6.[ (x + 1/4)Â² - (1/12) ]
vertex when x = - 1 / 4 , y = - 1/2
vertex is V(- 1/4, - 1/2)

2007-04-21 05:30:33 · answer #2 · answered by Como 7 · 1⤊ 2⤋

My eyes! My eyes!!

Sorry. Math phobia.

My God. Is this even math?!?

Sandy

2007-04-21 05:15:44 · answer #3 · answered by Sandy M 5 · 0⤊ 4⤋